document.write( "Question 136864: PROBLEM:
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document.write( "DAVE IS FLYING FROM PHILADELPHIA TO CHICAGO. ON THE FLIGHT, FLYING AGAINST THE WIND, THE 780 MILE TRIP TAKES 2 HOURS. THE RETURN TRIP, WITH THE WIND TAKES 1.5 HOURS. FIND THE SPEED OF THE WIND AND FIND THE SPEED OF THE PLANE IN STILL AIR.\r
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document.write( "PLEASE HELP I DONT EVEN KNOW WHERE TO BEGIN THANKS!! \n" );
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Algebra.Com's Answer #100159 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 780/2=390 MPH AGAINST THE WIND \n" ); document.write( "780/1.5=520 MPH WITH THE WIND \n" ); document.write( "(520-390)/2=130/2=65 MPH FOR THE WIND SPED. \n" ); document.write( "PROOF: \n" ); document.write( "520-65=390+65 \n" ); document.write( "455=455 THIS IS THE SPEED OF THE PLANE IN STILL AIR. \n" ); document.write( " \n" ); document.write( " |