document.write( "Question 20867: How do you find the vertex and axis of symmetry in a quadratic equation?
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Algebra.Com's Answer #10015 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING 2 EXAMPLES TO KNOW THE METHOD\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "********************************************************************************* \n" ); document.write( "LET Y=X^2+4X+5.. \n" ); document.write( "GRAPHICAL METHOD..................... \n" ); document.write( "GIVE DIFFERENT VALUES TO X AND FIND CORRESPONDING Y VALUE TABULATE..TAKE A SUITABLE SCALE AND PLOT FOR GRAPH \n" ); document.write( "X......0....1.......2....3....-1....-2....-3.....-4.......-5.........-6...........-7 \n" ); document.write( "Y.....5....10.....17...26...2.....1.....2......5......10.........17..........26 \n" ); document.write( "FROM TABLE/GRAPH YOU CAN SEE THAT THE VERTEX IS AT X=-2 AND Y=1.....,AXIS OF SYMMETRY IS X=-2.......THERE IS A MINIMUM OF Y=1 AT THE VERTEX GIVEN ABOVE..........\r \n" ); document.write( "\n" ); document.write( "ANALYTICALLY YOU CAN DO LIKE THIS \n" ); document.write( "Y=X^2+4X+4-4+5=(X+2)^2+1.....NOW (X+2)^2 BEING A SQUARE IS ALWAYS POSITIVE.SO ITS MINIMUM VALUE IS ZERO WHEN X=-2..AT THAT X=-2 ,MINIMUM VALUE OF Y OCCURS =0+1=1......NOW TAKING THIS AS VERTEX WE OBSERVE THAT ON EITHER SIDE OF X=-2,THAT IS SAY 5 UNITS ON EITHER SIDE OF X=-2...THAT IS X=-2+5=3 AND X=-2-5=-7......Y HAS SAME VALUE NAMELY (-7+2)^2+1=(-5)^2+1=26=(3+2)^2+1=5^2+1...SO X=-2 IS THE AXIS OF SYMMETRY.... \n" ); document.write( "I HOPE YOU CAN DO THE SECOND PROBLEM BY YOUR SELF NOW WITH THESE EXAMPLES GIVEN TO YOU. \n" ); document.write( "VENUGOPAL \n" ); document.write( "- Show quoted text - \n" ); document.write( "****************************************************************************** \n" ); document.write( "SEE RECENT ANSWERS GIVEN BY ME IN ALGEBRA.COM FOR THIS ...PROBLEM NO.20847,ANSWER NO.10010 DT 29TH.NOV.05....GIVEN BELOW\r \n" ); document.write( "\n" ); document.write( "LET Y= \n" ); document.write( "GIVE DIFFERENT VALUES TO X IN THE ABOVE EQUATION AND FIND CORRESPONDING VALUES OF Y..TABULATE AS FOLLOWS,CHOOSE A SUITABLE SCALE AND PLOT THEM ON A GRAPH AS SHOWN BELOW \n" ); document.write( "X....0.....1......2.....3.......4......ETC.. \n" ); document.write( "Y....-1....2......3.....2.......-1\r \n" ); document.write( "\n" ); document.write( " |