document.write( "Question 136740: Hi,
\n" ); document.write( " Can you help me with this math problem?\r
\n" ); document.write( "\n" ); document.write( "Solve the problem.
\n" ); document.write( "15.) The sum of the squares of the digits of a positive two-digit number is 20, and the tens digit is 2 more than the units digit. Find the number. \r
\n" ); document.write( "\n" ); document.write( "The answer should be 42
\n" ); document.write( "

Algebra.Com's Answer #100106 by Earlsdon(6294)\"\" \"About 
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Try this!
\n" ); document.write( "Let T = the ten's digit and U = the unit's digit.
\n" ); document.write( "Then:
\n" ); document.write( "\"T%5E2%2BU%5E2+=+20\" and...
\n" ); document.write( "\"T+=+U%2B2\" Substitute this into the above equation:
\n" ); document.write( "\"%28U%2B2%29%5E2%2BU%5E2+=+20\" Simplify:
\n" ); document.write( "\"U%5E2%2B4U%2B4%2BU%5E2+=+20\"
\n" ); document.write( "\"2U%5E2%2B4U%2B4+=+20\" Subtract 20 from both sides.
\n" ); document.write( "\"2U%5E2%2B4U-16+=+0\" Factor out a 2.
\n" ); document.write( "\"2%28U%5E2%2B2U-8%29+=+0\" Apply the zero products rule.
\n" ); document.write( "\"U%5E2%2B2U-8+=+0\" Factor.
\n" ); document.write( "\"%28U%2B4%29%28U-2%29+=+0\" so...
\n" ); document.write( "\"U%2B4+=+0\" or \"U-2+=+0\", then...
\n" ); document.write( "\"U+=+-4\" or \"U+=+2\" Discard the negative solution.
\n" ); document.write( "\"U+=+2\" This is the unit's digit.
\n" ); document.write( "\"T+=+U%2B2\"
\n" ); document.write( "\"T+=+2%2B2\"
\n" ); document.write( "\"T+=+4\" This is the ten's digit.
\n" ); document.write( "The number (TU) is 42.
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