document.write( "Question 136731: not sure if in right category
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document.write( "but when the question is like jill does this in 30 min
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document.write( "bob does it in 45
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document.write( "sue takes an hour and a half
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document.write( "how long does it take all of them to do it together
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document.write( "i have no idea how to solve this problem \n" );
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Algebra.Com's Answer #100095 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Jill does the job in 30 minutes or 1/2 hour. So turn the fraction over and Jill can do 2/1 or 2 jobs per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Bob does the job in 45 minutes or 3/4 hour. Bob can do 4/3 job per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sue does the job in 3/2 hour. Sue can do 2/3 job per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 plus 4/3 plus 2/3 = 6/3 + 4/3 + 2/3 = 12/3 = 4 jobs per hour working together.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Turn the fraction (4/1) over again, and together they can do the job once in 1/4 hour or 15 minutes. \n" ); document.write( " |