document.write( "Question 136646: Daniel's Print Shop purchased a new printer for $35,000. Each year it depreciates (loses value) at a rate of 5%. What will its approximate value be at the end of the fourth year? \n" ); document.write( "
Algebra.Com's Answer #100064 by smartcookie(2)\"\" \"About 
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The equation need to solve this problem is y=a(b)^x
\n" ); document.write( "a= the starting value
\n" ); document.write( "b= the rate of change
\n" ); document.write( "x= the time\r
\n" ); document.write( "\n" ); document.write( "to get the rate of change do the following:
\n" ); document.write( " add 1 to the percentage of change (only if value is growing)
\n" ); document.write( " subtract the percentage from one (only if value is decaying)\r
\n" ); document.write( "\n" ); document.write( "Since the printer is depreciating it is a decay.\r
\n" ); document.write( "\n" ); document.write( "The rate of change for this problem is showed below.
\n" ); document.write( "1-0.05
\n" ); document.write( "0.95 is the rate of change.
\n" ); document.write( "Below is the equation for the problem.
\n" ); document.write( "y=35000(0.95)^4 Work the problem.
\n" ); document.write( "Y=35000(0.814506250
\n" ); document.write( "Y=28507.71875 Since we are working with money we round to two decimal places.\r
\n" ); document.write( "\n" ); document.write( "The printer's value after four years is $28,507.72.
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