document.write( "Question 136608: The length of a rectangle is 6 in. more than twice its width. Its area is 108in(square). Find the length of the rectangle \n" ); document.write( "
Algebra.Com's Answer #100059 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+6 \n" ); document.write( "W(2W+6)=108 \n" ); document.write( "2W^2+6W-108=0 \n" ); document.write( "2(W^2+3W-54=0 \n" ); document.write( "2(W+9)(W-6)=0 \n" ); document.write( "W-6=0 \n" ); document.write( "W=6 FOR THE WIDTH MEASUREMENT. \n" ); document.write( "L=2*6+6 \n" ); document.write( "L=12+6 \n" ); document.write( "L=18 IS THE LENGTH MEASUREMENT. \n" ); document.write( "PROOF: \n" ); document.write( "6(2*6+6)=108 \n" ); document.write( "6(12+6)=108 \n" ); document.write( "6*18=108 \n" ); document.write( "108=108 \n" ); document.write( " |