document.write( "Question 136601: A cyclist traveled at a rate of 24mph to visit a nearby town. The cyclist averaged 18mph on the return trip. If the round trip took 4.9 hours, find the distance to the nearby town.\r
\n" ); document.write( "\n" ); document.write( "I am not sure how to work this one. I know that D=R(T). But I am confused because I have a combined round trip time instead of a time going and a time coming back.
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Algebra.Com's Answer #100038 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Time for outbound trip: \"t%5B1%5D\"
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\n" ); document.write( "\n" ); document.write( "For the outbound trip: \"d=24t%5B1%5D\", but that can be expressed as \"t%5B1%5D=d%2F24\"
\n" ); document.write( "For the return trip: \"t%5B2%5D=d%2F18\"\r
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\n" ); document.write( "\n" ); document.write( "But \"t%5B1%5D%2Bt%5B2%5D=4.9\", so \"%28d%2F24%29%2B%28d%2F18%29=4.9\"\r
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\n" ); document.write( "\n" ); document.write( "LCD for 24 and 18 is 72 (3 * 24 = 4 * 18 = 72)\r
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\n" ); document.write( "\n" ); document.write( "\"3d%2F72%2B4d%2F72=4.9\"\r
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\n" ); document.write( "\n" ); document.write( "\"7d=4.9%2A72\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=.7%2A72=50.4\"\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Outbound trip: \"t%5B1%5D=50.4%2F24=2.1h\"
\n" ); document.write( "Return trip: \"t%5B2%5D=50.4%2F18=2.8h\"\r
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\n" ); document.write( "\n" ); document.write( "\"t%5B1%5D%2Bt%5B2%5D=2.1%2B2.8=4.9\" Answer checks.
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