document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2354>Question 2354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm confused about the whole Slope deal. I dont really understand the equations for it. I know that the equation is y=mx+b but how do you solve a problem that is like 10y - 12x = 8?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1000 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> re-arrange it to the form you need, ie 1y equals, like so...\r<BR>\n" );
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document.write( "10y-12x=8<BR>\n" );
document.write( "10y = 12x + 8<BR>\n" );
document.write( "y = 1.2x + 0.8\r<BR>\n" );
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document.write( "so now, m=1.2 ie the gradient is +1.2 (just over 1). A gradient of 1 is a line at 45 degrees (for equal scales on the 2 axes)\r<BR>\n" );
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document.write( "jon<BR>\n" );
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