document.write( "Question 23: what are the roots if in ractored form it is y=(2x-3)(3x+4)?\r
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Algebra.Com's Answer #10 by AnlytcPhil(1806)\"\" \"About 
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>>what are the roots if in factored form it is y=(2x-3)(3x+4)?<<
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document.write( "The \"roots\" are found by replacing y by 0 and solving for x
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document.write( "y = (2x-3)(3x+4)
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document.write( "0 = (2x-3)(3x+4)
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document.write( "set each parenthetical factor = 0
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document.write( "2x-3=0, or x = 3/2
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document.write( "3x+4=0, or x = -4/3
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document.write( "what is the axis of symmetry?
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document.write( "The equation of the axis of symmetry is
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document.write( "x = (the average of the two roots)
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document.write( "or rather:
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document.write( "x = (r1 + r2)/2
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document.write( "x = [(3/2) + (-4/3)]/2 
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document.write( "x = (3/2 - 4/3)/2
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document.write( "x = (9/6 - 8/6)/2
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document.write( "x = (1/6)/2
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document.write( "x = 1/12
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document.write( "That's its equation, x = 1/12
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document.write( "Edwin \n" );
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