# SOLUTION: The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the lenghth of the base. If the perimeter is 29cm, find the lenghth of the equal legs.

Algebra ->  Calculators  -> Pythagorean Theorem Solver, Cartoon Lesson, and practice -> SOLUTION: The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the lenghth of the base. If the perimeter is 29cm, find the lenghth of the equal legs.       Log On

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 Question 99612: The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the lenghth of the base. If the perimeter is 29cm, find the lenghth of the equal legs. Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the lenghth of the base. If the perimeter is 29cm, find the lenghth of the equal legs. ---------------- Let the length of the base be "x" cm. Leg = 4x-8 Other leg = 4x-8 ------------- EQUATION: x + 2(4x-8) = 29 9x - 16 = 29 9x = 45 x = 5 cm (length of the base) 4x-8 = 12 cm (length of one of the equal legs) ============== Cheers, Stan H.