SOLUTION: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field
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If the perimeter of the playing field is 230 ft, find the length and width of the field
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Question 87368: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field Answer by rossiv53(27) (Show Source):
You can put this solution on YOUR website! Ok, so begin by assigning a variable for width.
Width = W
We know that length is 5 feet less than twice the width. So, L=2W-5
Perimeter is equal to the value of all four sides.
So, W+W+(2W-5)+(2W-5)=230 ft
2W+2(2W-5)=230
2W+4W-10=230
6W-10=230
6W-10+10=230+10
6W=240
W=40 This is width
L=2(40)-5
L=75
75+75+40+40=230ft
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