# SOLUTION: Hello i have a question A bicyclist rode into the country for 5/h in returning her speed was 5 mi/h faster and the trip took 4/h. What was her speed each way? Thank you so mu

Algebra ->  Calculators  -> Pythagorean Theorem Solver, Cartoon Lesson, and practice -> SOLUTION: Hello i have a question A bicyclist rode into the country for 5/h in returning her speed was 5 mi/h faster and the trip took 4/h. What was her speed each way? Thank you so mu      Log On

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 Click here to see ALL problems on Geometry Word Problems Question 8070: Hello i have a question A bicyclist rode into the country for 5/h in returning her speed was 5 mi/h faster and the trip took 4/h. What was her speed each way? Thank you so much for your help a momAnswer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!You can use the distance formula: d = rt (distance = rate X time) For the outbound trip: d1 = (r1)(t1) d1 = (r1)(5 hrs) For the return trip: d2 = (r2)(t2) d2 = (r2)(4 hrs) But, d1 = d2 (Same distance outbound as return) And, r2 = r1+5 (Return speed was 5 mph more than the outbound speed) So we can write: d1 = d2 or; (r1)(5) = (r1+5)(4) Simplify and solve for r1. 5(r1) = 4(r1) + 20 r1 = 20 mph Outbound speed. r2 = r1+5 mph = (20+5) mph = 25 mph Return speed.