SOLUTION: A rectangle is 10m longer than it is wide.If its length and width are both decreased by 2 m,its area is decreased by 48 m squared.Find its original dimensions.

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Question 64022This question is from textbook Algebra Structure and Method Book1
: A rectangle is 10m longer than it is wide.If its length and width are both decreased by 2 m,its area is decreased by 48 m squared.Find its original dimensions. This question is from textbook Algebra Structure and Method Book1

Answer by checkley71(8403) About Me  (Show Source):
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L*W=AREA
(W+10)W=(W-10-2)(W-2)+48
W^2+10W=(W-12)(W-2)+48
W^2+10W=W^2-12W-2W+24+48
10W+14W=72
24W=72
W=72/24
W=3 SOLUTION
L=3+10=13 SOLUTION
PROOF
13*3=(3-12)(3-2)+48
39=-9*1+48
39=-9+48
39=39