SOLUTION: there are 3 concentric rectangles. the length of the outer rectangle is twice the legth of inner rectangle and so is the case with the breadth. the middle rectangle is equidistant

Algebra ->  Calculators  -> Pythagorean Theorem Solver, Cartoon Lesson, and practice -> SOLUTION: there are 3 concentric rectangles. the length of the outer rectangle is twice the legth of inner rectangle and so is the case with the breadth. the middle rectangle is equidistant       Log On


   

Question 617246: there are 3 concentric rectangles. the length of the outer rectangle is twice the legth of inner rectangle and so is the case with the breadth. the middle rectangle is equidistant from both the rectangles. then the area of the middle rectangle is
Answer by Theo(3464) About Me  (Show Source):
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area of the inner rectangle is equal to L*W
area of the outer rectangle is equal to 2*L*2*W = 4*L*W
area of the middle rectangle is equal to 1.5*L*1.5*W = 2.25*L*W
example:
inner rectangle L = 10
inner rectangle W = 8
outer rectangle L = 20
outer rectangle W = 16
middle rectangle L = (20-10)/2 + 10 = 10/2 + 10 = 5 + 10 = 15
middle rectangle W = (16-8)/2 + 8 = 8/2 + 8 = 4 + 8 = 12
area of inner rectangle = 10*8 = 80
area of outer rectangle = 20*16 = 320 = 4*80
area of middle rectangle = 15*12 = 180 = 2.25*80