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The length of the first rectangle is 4cm more than the length of the second.
The width of the first is 9cm.
The width of the second is 6cm.
If the area of the first rectangle is 96 square cm greater than the area of the second, find the length of each.
Let's do it this way.
Let a = the length of the 2nd rectangle
(a+4) = the length of the 1st rectangle
1st rect area - 2nd rect area = 96 sq/cm
9(a+4) - 6a = 96
9a + 36 - 6a = 96
9a - 6a = 96 - 36
3a = 30
a = 30/3
a = 10 cm is the length of the 2nd rectangle
10+4 = 14 cm is the length of the 1st rectangle
9*14 - 6*10 =
126 - 30 = 96; confirms our solution