Question 4591: If the inside circumference of a circle is 72" what would the outside circumferece br 6" out from inter circle? Answer by xcentaur(357) (Show Source):
You can put this solution on YOUR website! c=2*pi*r=72"
r=72/2*pi
R=r+6=(72/2*pi)+6
C=2*pi*R
=2*pi
=2*pi
=72+12*pi
=72+(12*22/7)
=72+(264/7)
=(504+264)/7
=768/7
=109.714"