SOLUTION: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. a) Set up an equation for the perimeter involving o

Algebra ->  Calculators  -> Pythagorean Theorem Solver, Cartoon Lesson, and practice -> SOLUTION: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. a) Set up an equation for the perimeter involving o      Log On


   

Question 240956: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
a) Set up an equation for the perimeter involving only L, the length of the rectangle.
Answer:
b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
Answer: Length 22.5, Width 19.5
Show your work here:W=L-3
2W+2L=84
2(L-3)+2L=84
2L-6+2L=84
4L=84+6
4L=90
L=90/4
L=22.5 ANS. FOR THE LENGTH.
W=22.5-3=19.5 ANS. FOR THE WIDTH.
PROOF:
2*19.5+2*22.5=84
39+45=84
84=84

Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
W=L-3
2W+2L=84
2(L-3)+2L=84
2L-6+2L=84
4L=84+6
4L=90
L=90/4
L=22.5 ANS. FOR THE LENGTH.
W=22.5-3=19.5 ANS. FOR THE WIDTH.
PROOF:
2*19.5+2*22.5=84
39+45=84
84=84