# SOLUTION: The base of a triangle is 2cm shorter than the width of a rectangle. The rectangle's length is 4 times the width and the triangle's height is twice the rectangle's length. Find the

Algebra ->  Calculators  -> Pythagorean Theorem Solver, Cartoon Lesson, and practice -> SOLUTION: The base of a triangle is 2cm shorter than the width of a rectangle. The rectangle's length is 4 times the width and the triangle's height is twice the rectangle's length. Find the      Log On

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Question 197128: The base of a triangle is 2cm shorter than the width of a rectangle. The rectangle's length is 4 times the width and the triangle's height is twice the rectangle's length. Find the area of each figure if the difference of their areas is 30m^2.Answer by edjones(7569)   (Show Source): You can put this solution on YOUR website!Let w=width of the rectangle. base of triangle=w-2 length of rectangle=4w height of triangle=8w Area of rectangle=4w^2 area of triangle=8w(w-2)/2 =4w^2-8w which is smaller than the area of the rectangle. 4w^2-(4w^2-8w)=30 4w^2-4w^2+8w=30 8w=30 . w=3.75 4w=15 15*3.75=56.25m^2 area of rectangle. . 8w=30 w-2=1.75 30*1.75/2=26.25m^2 area of triangle . Ed