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Question 151690: I tried to set this up numerous ways and was not coming up with anything I could use.
How many milliliters of a 50% saline solution must be mixed with 60 milliliters of a 15% saline solution to obtain a 40% saline solution?: I tried to set this up numerous ways and was not coming up with anything I could use.
How many milliliters of a 50% saline solution must be mixed with 60 milliliters of a 15% saline solution to obtain a 40% saline solution?
Answer by nerdybill(1130) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = amount of 50% saline solution added
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"amt of saline from added solution" + "amt of saline in org solution" = "desired amt of saline"
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.50x + .15(60) = .40(60+x)
.50x + 9 = 24 + .40x
.10x + 9 = 24
.10x = 15
x = 15/.10
x = 150 milliliters