SOLUTION: The blade on a table saw rotates at 3450 revolutions per minute. How much faster (in ft/sec) does a 12-in. -diameter blade strike a piece of wood than a 10-in. -diameter blade?

Question 625856: The blade on a table saw rotates at 3450 revolutions per minute. How much faster (in ft/sec) does a 12-in. -diameter blade strike a piece of wood than a 10-in. -diameter blade?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The blade on a table saw rotates at 3450 revolutions per minute. How much faster (in ft/sec) does a 12-in. -diameter blade strike a piece of wood than a 10-in. -diameter blade?
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3450 rpm = 57.5 rev/sec
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10" : C = pi*d = 10pi inches = 5pi/6 ft
--> (5pi/6)*57.5 ft/sec
=~ 150.5 ft/sec
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12" : C = pi ft
--> 57.5pi ft/sec
=~ 180.6 ft/sec
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The speeds are in the ratio 5 to 6, same as the blade sizes
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