SOLUTION: A jogger runs at an average speed of 5.9mi/hr. If she starts a run at 11:15 am, what time is it after she covers 4.75 x 10^4 ft?

Question 307378: A jogger runs at an average speed of 5.9mi/hr. If she starts a run at 11:15 am, what time is it after she covers 4.75 x 10^4 ft?
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
First I would change the rate of 5.9 mi/hr to feet per minute. To do this multiply by 5280 feet per mile, and divide by 60 to change the hours to minutes.

Rate = 5.9 * 5280/60= 519.2 feet per minute.

Now, the distance to be run is 4.75x10^4 =47500 feet.

Use the formula to solve for t, .
minutes, or 1 hour and 31.48 minutes.

Add this to the starting time of 11:15 a.m., and you get
11:15+ 1:31 = 12:46 p.m. approximately.

Dr. Robert J. Rapalje, Retired
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