SOLUTION: This is the last one. u2 - 13u + 40/3u2 - 33u + 90 This is one big fraction again. the 2's after both u's are 'to the power 2's" Again I just do not no where to start.

SOLUTION: This is the last one. u2 - 13u + 40/3u2 - 33u + 90 This is one big fraction again. the 2's after both u's are 'to the power 2's" Again I just do not no where to start.

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Question 225722: This is the last one. u2 - 13u + 40/3u2 - 33u + 90 This is one big fraction again. the 2's after both u's are 'to the power 2's" Again I just do not no where to start.
Answer by LtAurora(115) (Show Source): You can put this solution on YOUR website!

Have to factor the num. and den.:
So, the num. factors with 8 and 5, which add to give us the 13:

The den. has a GCF of 3, so pull that out first:

Then factor the remaining bit with 6 and 5, which add to give us the 11:

Rewrite as a fraction:

Here we can see that the u-5 cancels, which leaves:

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