SOLUTION: Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square min

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Question 224482: Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square minute. Round answer to tenths place.
Answer by ankor@dixie-net.com(12704) About Me  (Show Source):
You can put this solution on YOUR website!
Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square minute. Round answer to tenths place.
:
26s^2
:
26 ft accelerated for 1 min
:
26(60^2) = 93,600 ft which is 93600%2F5280 = 17.7 mi
:
17.7m^2
:
:
See if that is true, check using 2 min (120 sec)
26(120^2) = 374400 ft which is 374400%2F5280 = 70.9 miles
and
17.7(2^2) = 70.8 miles, close enough