SOLUTION: Factor Z2-3z-18 and 5z2+17z+14 Both the "2" next to the z's are supposed to be the to the power kind of two;s but have no idea how to make them. Can someone please explain to me h

Question 221629: Factor Z2-3z-18 and 5z2+17z+14 Both the "2" next to the z's are supposed to be the to the power kind of two;s but have no idea how to make them. Can someone please explain to me how to factor?????????
Thanks
Deb
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!

ok, so here is how i do these, i will break it down into ( )( ) a set of parenthesis, then i see what can i put in there? well in order to get the first term, we can either have z times z or z^2 times 1. The second one won't work since we have to have z+something times z-something soooo...
AMP Parsing Error of [(z+?)(z-?)]: Invalid expression '?)(z-?)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . now we look at the third term, which is 18,how can we get 18? well we can do 6 times 3, 9 times 2 or 18 times 1. How do you know which one we need? Well the middle terms decides that, we need -6 and +3, if we add them, we will have -3 which is the coefficient of the third term.
and just to verify this is equal to z^2-6z+3z-18=z^2-3z-18
next one
feel free to check the answer, but it is correct.
Good luck Deb!!!! =)
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