SOLUTION: 420 g of food was placed in a hamster’s cage. On the first day, the hamster ate {{{2/5}}} of the food. On the second day, the hamster ate {{{1/3}}} of the food. On the third

Question 1184563: 420 g of food was placed in a hamster’s cage.
On the first day, the hamster ate of the food.
On the second day, the hamster ate of the food.
On the third day, the hamster ate 41 g of the food and some food was left.
(a) Find the mass of food the hamster ate on the first day.
(b) Find the mass of food left at the end of the third day.
Found 3 solutions by Boreal, josgarithmetic, MathTherapy:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
day 1 ate 420(2/5)=168 gm so 252 gm left.
day 2 ate 1/3 of that or 84 gm so have 168 gm left
day 3 ate 41 gm so 127 gm left.
First and third lines are the answers.
I am assuming on the second day ate 1/3 of the remaining food, not 1/3 of the original amount.
Answer by josgarithmetic(39627)   (Show Source): You can put this solution on YOUR website!
Hamster finished still retained this much after the second day:
according to the description.

Retained at end of second day

On the day #3, hamster ate 41 grams of food. He then had retained .
Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

420 g of food was placed in a hamster’s cage.
On the first day, the hamster ate of the food.
On the second day, the hamster ate of the food.
On the third day, the hamster ate 41 g of the food and some food was left.
(a) Find the mass of food the hamster ate on the first day.
(b) Find the mass of food left at the end of the third day.

(a) Amount eaten on 1st day:
(b) Amount remaining at the end of the 3rd day:
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