.
x for oranges' calories
y for strawberries' calories
2x + 3y = 112 (1)
3x + 4y = 165 (2)
Multiply first equation by 3 (both sides) and the second equation by 2. You will get
6x + 9y = 336 (3)
6x + 8y = 330 (4)
Subtract equation (4) from equation (5). The terms "6x" will cancel each other
and you will get single equation for the unknown y only
9y - 8y = 336 - 330
y = 6.
So, we have 6 calories for each strawberry.
Now substitute y= 6 into very first equation. You will get
2x + 3*6 = 112
2x = 112 - 18 = 94
x = 94/2 = 47.
ANSWER. 47 calories for each orange and 6 calories per strawberry.
CHECK. Make checking on your own by substituting the found values into the original equations.
Solved.