SOLUTION: Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few

Question 1092077: Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 8 inches of water to the depth of the pool, using her garden hose. Although her water pressure varies, the water flows through Jill�s garden hose at an average rate of 10 gallons/minute.
Convert the dimensions of the pool to meters. Round all meter measurements to one decimal place (nearest tenth of a meter).
How many liters will Jill need to add to her pool to return the water level to its original depth? How many gallons of water is this? Reminder: Volume = Length x Width x Depth
How long will Jill need to run the hose? Express your answer in hours and minutes.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The pool is 4.955 m wide and 7.965 m long, or 5.0 m x 8.0 m
Depth is 1.5 m
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She adds water to increase the depth 0.2 m.
Volume of pool at full depth is 60 m^3, 5*8*1.5
Volume of pool when at 1.3 m deep is 52 m^3.
She needs to replace 8 m^3 of water, and that is 8m^3*100 cm/m*100 cm/m*100 cm/m=8,000,000 cm^3
There are 1000 cm^3 per liter, so this is 8000 liters
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The hose runs at 10 gallons a minute or 37.9 liters/minute
8000 liters/37.9 liters/minute = 211.08 minutes or 3h31m

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