SOLUTION: The base of a triangle is 4 dm longer than the altitude, and its area is 16 dm^2. Find the lengths of the base and the altitude.

Question 1044245: The base of a triangle is 4 dm longer than the altitude, and its area is 16 dm^2. Find the lengths of the base and the altitude.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
The base b of a triangle is c dm longer than the altitude h, and its area is A dm^2. Find the lengths of the base and the altitude.

Answer by MathTherapy(10553) (Show Source): You can put this solution on YOUR website!

The base of a triangle is 4 dm longer than the altitude, and its area is 16 dm^2. Find the lengths of the base and the altitude.

Let altitude be A
Then base = A + 4
We then get:

------ Cross-multiplying

(A - 4)(A + 8) = 0

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