SOLUTION: Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to c

Question 1019528: Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 day?
Found 2 solutions by robertb, MathTherapy:
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The total number of man hours (for the first 6 days) required to finish 5/21 of the work is 10*6*10 = 600 man-hours. Hence each man contributes for the entire job.
Now 16/21 of the job still had to be done, and the job had to be done at the same rate and at the same number of hours each day.
Note that 16/21 of the job had to be completed in 2 more days. (2 additional days after initial 6 days.)
Let m = number of men required to complete the job in two more days
Hence...

==>
==> m = 96.
Therefore it will take 96 men to finish the job in two more days at the same rate and same number of hours each day.

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Ten men working for 6 days of 10 hours each, finish 5/21 of a piece of work . How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 day?

It'll take men, working 8 days, @ 10 hours each day, or 80 hours to complete the remaining of job
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