Tutors Answer Your Questions about Travel Word Problems (FREE)
Question 43975: Corbin Ecles and Connor Hayes have received walkie talkies for Christmas. If they leave from the same point at the same time, Corbin walking north at 2.5 mph and Connor walking east at 3 mph, how lone will they be able to talk to each other if the range of the walkie-talkies is 4 mi?
Click here to see answer by adamchapman(301)  |
Question 44181: Can anyone help? I need to solve this problem with work shown:
Show a complete solution to each problem.
Big Plane. A six passenger plane cruises at 180 mph in calm air. If the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind then what is the wind speed?
Click here to see answer by stanbon(57361) |
Question 44207:
A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20% grade, or slope. If the vertical height at the end of the ramp must be 11 ft to assure that the stunt is a success, what must be the length of the horizontal run?
Click here to see answer by adamchapman(301) |
Question 44544: A car leaves a town at 40 miles per hour. Two hours later a second car leaves the town traveling the same route and overtakes the first car in 5 hours and 20 minutes. how fast was the second car traveling?
Click here to see answer by Nate(3500) |
Question 44502: An athlete ran for 8 hours at a constant speed. The athlete was immediately given a bike and rode in the opposite direction for 3 hours, with twice the speed. The athlete then reversed direction again, walking for 1 hour at 40% of initial running speed. After 12 hours, the athlete was 9.6 miles from the point where the marathon exercise excursion began. Find the athlete’s three speeds.
Click here to see answer by stanbon(57361) |
Question 44566: I think I am doing something wrong maybe someone can tell me what Did wrong.
The question is Brian starts walking from point A at 2 mph. One-half hour later, Elliott starts walking from point A 3 1/2 mph follows the same route.
How long will it take Elliott to catch up with Brian?
This is what I did
RATE x TIME = DISTANCE
BRIAN_ 2 x 2x
ELLIOTT 3.5 1.5 3.5 (1.5)
2x=3.5(1.5)
2x=5.25
x= 2.62
is this right?????
Click here to see answer by stanbon(57361) |
Question 44805: Corhin Eckles and Connor Hayes have recieved walkie talkies for Christmas. If they leave from the same point at the same time, Corhin walking north at 2.5 mph and Connor walking east at 3 mph, how long will they be able to talk to each other if the range of the walkie-talkies is 4 mi?
acrown1@umbc.edu
Click here to see answer by stanbon(57361) |
Question 44979: Sally can ride her bike 8 mph faster than she can run. She rode her bike for 4 1/2 miles and then ran the other 2 miles. Her total time of running and biking was an hour. How fast was she running and how fast was she biking?
Click here to see answer by Paul(988) |
Question 45170: Hi, I have a problem that reads: "The balloon traveled 48 miles in 4 hours. It's speed was then increased by 8 mph. If the total they traveled was 108 miles, how much time did it need for the entire trip?" This is what I did: I subtracted 48 miles from the total 108 miles it traveled and got 60. Then I divided 48 miles by 4 hours and got 12 mph. Then I added 8 mph increase to the 12 mph and got 20 mph, which I used to divide the 60 miles by, and got 30 hours. Is that right? (the answer is a total of 34 hours?) Also, if this is for Algebra, can I just show my work as simple subtraction, addition, and dividing or do I have to write some equation? It doesn't say to do that.. Thank you!
Click here to see answer by Nate(3500) |
Question 45237: Please help. A plane made a flight with the wind between 2 towns in 2 hours. Returning against the wind, the planes speed was 60 mph slower and the flight took 3 hours. What was the planes speed in each direction.
Click here to see answer by checkley71(8403) |
Question 45237: Please help. A plane made a flight with the wind between 2 towns in 2 hours. Returning against the wind, the planes speed was 60 mph slower and the flight took 3 hours. What was the planes speed in each direction.
Click here to see answer by stanbon(57361) |
Question 45987: I would appreciate any help. It is from an online test:
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Click here to see answer by Earlsdon(6287) |
Question 46652: Show a complete solution to each problem.
Big Plane. A six passenger plane cruises at 180 mph in calm air. If the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind then what is the wind speed?
Thanks
Click here to see answer by adamchapman(301) |
Question 46681: Going skiing. Leon drove 270 miles to the lodge in the same time as pat drove 330 miles to the lodge. If Pat drove 10 miles per hour faster than Leon, then how fast did each of them drive?
Click here to see answer by Paul(988) |
Question 46713: Two riders on bicycles, 100 miles apart, begin traveling toward each other at the same time, one traveling at 10 mph and the other at 15 mph. A fly begins flying between the bicycles, starting from the front wheel of the slower bicycle. If the fly travels at 20 mph flying back and forth between bicycles, being able to reverse directions without losing any time, how far will the fly tarvel before the bicycles meet?
HERE IS A COPY OF WHAT I HAVE ATTEMPTED:
Step 1
Now you need to identify the unknown. An unknown is a quantity that you problem requires you to find out, or the quantity that is necessary to find out in order to obtain the solution.
What is the unknown in this problem?
There are several ways to define the unknown in this problem. We are using one of them. They all lead to the same result.
Please choose one answer.
o The time of their trip, and the distance from where they start to the point of their meeting.
o The difference between their speeds
You should have chosen the time of their trip.
Since the time of the trip is what the problem asks for, you can choose it as your unknown in this case. Note that for other problems, it may be more convenient to choose something else as the unknown, calculate its value, and then use it to come up with the answer to the problem.
Step 2: Now you need to find out the equation needed to solve the problem. The critical piece that you need is the fact that the two riders are at one point at the same time at the moment when they meet. Let’s denote the distance from the Start of the boy rider to that point as X. The distance from the girl to that point is 100-X.
The time t1 it takes the boy to reach the meeting point is x divided by his speed.
The time t2 it takes the girl to reach the meeting point is 100-X divided by its speed.
Since both riders are in the meeting point at the same time, these two times are equivalent. That is, t1=t2.
Please choose one answer.
o x/10 = (100-x)/15
o x/10 = x/15
Given the equation
x/10 = (100-x)/15,
we can simplify it as x/10 + x/15 = 100/15, or
x=10*100/(10+15)=40
The time that it takes the boy to travel 40 miles, is x divided by the speed he is going, which is
t=x/10=4
So, the answer is: 4 hours for the two riders to meet.
Now we have to figure Mr. Fly into the problem.
Now we have to find out how far Mr. Fly will travel before boy meets girl.
So far we know that Boy is going 10 mph so in 4 hours how far will he have gone?
Equation: 10mph * 4hrs = 40miles
Now MR. Fly is going 20mph and he is going back and forth between the boy and the girl. Mr. Fly is starting with the slower rider which is the boy going 10 mph. We need to find out how far Mr. Fly travels before boy and girl meet.
So let’s first find out how long and how far Mr Fly will travel before he meets Girl for the first time and then find out how far he went to make that first contact with Girl.
Now you need to find out the equation needed to solve the problem. The critical piece that you need is the fact that the Fly and the Girl area at one point on the line at the same time at the moment when the meet. Let’s denote the distance from Fly to that point as X. The distance from Girl to that point, is of course, 100-X.
The time t1 it takes the Fly to reach the meeting point is x divided by its speed.
The time t2 it takes the Girl to reach the meeting point is 100-X divided by her speed.
Since both trains are in the meeting point at the same time, these two times are equivalent. That is, t1=t2.
x/20 = (100-x)/15
we can simplify it as x/20 + x/15 = 100/15 or
x = 20 * 100/ (20=15) = 57.14 miles
The time that it takes the fly to travel 57.14 miles, is x divided by the speed of Mr Fly, which is
t = x/20 = 2.86 hours
The Fly is in front of the Boy. The Boy is going 10mph which is half the speed of the fly. So how far did the boy travel in 2.86 hrs?
10 mph * 2.86 = 28.6 miles
Girl went 42.86 miles
So in 2.86 hours the Boy went 28.6 miles. Mr Fly bounces off of Girl and immediately starts Flying back to the Boy. Do you know how far apart the Fly is from the Boy when Mr Fly bounces off of the Girl?
57.14 – 28.6 = 28.54
Mr Fly is flying at 20mph towards Boy who is going 10mph. There is 28.54 miles in between them.
What equation would we use?
The critically piece that you need is the fact that the Boy and Fly are at one point at the same time at the moment when they meet. Let’s denote the distance from Boy to that point as x. The distance from Fly to that point is, of course, 28.54-x.
The time t1 takes the Boy to reach the meeting point is x divided by its speed.
The time t2 it takes the Fly to reach the meeting point is 28.54-x divided by its speed
Since both trains are in the meeting point at the same time, these two times are equivalent. That is, t1 = t2.
x/10 = (28.54 – x) /20
we can simplify it as x/10 + x/20 = 28.54/20 or
x = 10 * 28.54 / (10 + 20) = 9.51
The time that it takes the Boy to travel 9.51 miles, is x divided by the speed of the Boy, which is
T = x / 10 = .951 hours.
So far Mr Fly has traveled 28.54 miles plus 9.51 miles = 38.05mi
Click here to see answer by Paul(988) |
Question 46935: I don't usually have trouble with these, but even with my little chart, I'm getting confused on how set up the problem.
A plane flies 720 mi against a steady 30 mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10h, what is the plane's speed in still air?
Click here to see answer by stanbon(57361) |
Question 47319: in an automobile race,the rate of one car was 120mi/hr and the rate of another was 105mi/hr. if the faster car finished the race 20 min before the slower one, what was the distance of the race?
Click here to see answer by Paul(988) |
Question 47427: A car enters a freeway traveling 50 kilometer per hour. One hour later another car enters the freeway by the same ramp, traveling 80 kilometer per hour. Determine the length of time before the second car overtakes the first car?
Click here to see answer by Nate(3500) |
Question 47424: A car enters a freeway traveling 50km/hr. One hour later another car enters the freeway by the same ramp, traveling 80km/hr. Determine the length of time before the second car overtakes the first car.
Click here to see answer by Nate(3500) |
Question 47556: From the Textbook:
Science and Medicine category. I need help solving the word problem and showing the equation I used to get the solution:
Martina leaves home at 9:00 am., bicycling at a rate of 24mi/h. Two hours later, driving at the rate of 48mi/h, at what time will John catch up with Martina?
Click here to see answer by josmiceli(9686)  |
Question 47553: From TEXTBOOK
Need help solving this word problem and I need to show the equation that was used to get the solution.
A bus leaves a station at 1 pm., travelling westat an average rate of 44mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48mi/h. At what time will two buses be 274 mi apart?
Thank You!
Click here to see answer by josmiceli(9686) |
Question 47552: Instructions: Solve the following word problem. Be sure to show the equation you use for the solution. (This is worded exactly from the text-book)
Science and medicine category:
A bicyclist rode into the country for 5 hours. In returning, her speed was 5mi/h faster and the trip took 4 hours. What was her speed each way?
Thank You very much for your help. I can work pretty much all algebra problems except word ones. I do not know what to do with the information given. I am a returning student to college after being out 20 years.
Click here to see answer by checkley71(8403) |
Question 47552: Instructions: Solve the following word problem. Be sure to show the equation you use for the solution. (This is worded exactly from the text-book)
Science and medicine category:
A bicyclist rode into the country for 5 hours. In returning, her speed was 5mi/h faster and the trip took 4 hours. What was her speed each way?
Thank You very much for your help. I can work pretty much all algebra problems except word ones. I do not know what to do with the information given. I am a returning student to college after being out 20 years.
Click here to see answer by stanbon(57361) |
Question 47500: I need your help with this problem:
Sound travels at 1100 ft./sec. in still air. Linda finds an old well on a farm she has just bought and wants to know how deep it is. She drops a rock from ground level and hears it splash 4.0 seconds later. Correct to the nearest whole foot, how deep is the well?
Click here to see answer by venugopalramana(3286) |
Question 47594: Wow. Everyone must be on vacation this week. This'll be the 3rd time I'm posting this one, so far no answer. help, it's due by tomorrow... =)
Ride the peaks. Smith bicycled 45 miles going east from Durango, and Jones bicycled 70 miles. Jones averaged 5 miles per hour more than Smith, and his trip took one-half hour longer than Smith’s. How fast was each one traveling?
Thanks
Click here to see answer by checkley71(8403) |
Question 47643: 4. Two cars started at the same time from towns 50 km apart and travelled toward each
other at uniform speed. They meet in 20 minutes and immediately started off again,
but this time, in the same direction, travelling at the same rates as before. Soon after,
the slower car stopped for 30 minutes and then started as usual. At what rate did each
car travel if, two hours after they started for the third town, they were 55 km apart?
Click here to see answer by venugopalramana(3286) |
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