SOLUTION: A student starting from his house walk at a speed of 2.5 km per hour and reaches his school 6 minute late. Next day at the same time he increases his speed by 1 km per hour and rea
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Question 994570: A student starting from his house walk at a speed of 2.5 km per hour and reaches his school 6 minute late. Next day at the same time he increases his speed by 1 km per hour and reaches 6 minute early. The distance between his school and house is?
Found 2 solutions by lwsshak3, MathTherapy:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A student starting from his house walk at a speed of 2.5 km per hour and reaches his school 6 minute late. Next day at the same time he increases his speed by 1 km per hour and reaches 6 minute early. The distance between his school and house is?
let x=distance between his school and house is?
x/2.5-x/3.5=12 min=1/6 hr
x/2.5-x/3.5=1/6
lcd: 2.5*3.5
3.5x-2.5x=8.75/6
x=1.4583 km
between his school and house is? 1.4583 km
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
A student starting from his house walk at a speed of 2.5 km per hour and reaches his school 6 minute late. Next day at the same time he increases his speed by 1 km per hour and reaches 6 minute early. The distance between his school and house is?
Distance: km
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