SOLUTION: Two planes are 485 mi apart and are traveling toward each other. One plane is traveling 150 mph faster than the other plane. The planes pass each other in 0.5 h. Find the speed of

Question 994018: Two planes are 485 mi apart and are traveling toward each other. One plane is traveling 150 mph faster than the other plane. The planes pass each other in 0.5 h. Find the speed of each plane.
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
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Let u be the speed of the faster airplane, in miles per hour (mph).

Then the speed of the other airplane is (u-150) miles per hour.

The equation is

0.5*u + 0.5*(u-150) = 485

(in half an hour airplanes flying toward each other covered the entire distance).

Simplify and solve it:

0.5u + 0.5u - 75 = 485,

u = 485 + 75

u = 560 .

The speed of the faster airplane is 560 miles per hour.

The speed of the other airplane is 560-150 410 miles per hour.

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