SOLUTION: A man intends to run a certain distance in 1/4 th less than he usually takes. By what percentage must he increase his running speed to accomplish this goal?
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Question 993999: A man intends to run a certain distance in 1/4 th less than he usually takes. By what percentage must he increase his running speed to accomplish this goal?
Answer by anand429(138) (Show Source): You can put this solution on YOUR website!
Let distance = d and time taken =t
so speed = d/t
New time = (3/4)t
So new speed = d/ (3t/4)
=4d/3t
increase in speed = 4d/3t -d/t
= d/3t
So, percentage increase in speed
=
= 33.33%
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