SOLUTION: Could someone please help me. So far I am doing well on my assignment with what I have learned from all of your help, it is these word problems that are tripping me up. Lee can

Question 99387: Could someone please help me. So far I am doing well on my assignment with what I have learned from all of your help, it is these word problems that are tripping me up.
Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate
:
Recognize the fact that the bicycle trip time = the car trip time
:
Let s = speed of the bicycle
Then
(s+30) = speed of the car
:
Write a time equation: Time = dist/speed
Bike time = Car time
=
:
Cross multiply
125s = 50(s+30)
125s = 50s + 1500
125s - 50s = 1500
75s = 1500
s = 1500/75
s = 20 mph is speed of the bicycle
:
20 + 30 = 50 mph is car's speed
:
:
Check solution by finding the time:
50/20 = 2.5 hrs
125/50 = 2.5 hrs, also
:

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