SOLUTION: A pilot flew a jet from A to B, a difference of 2500 km. On the return trip, the average speed was 20% faster than the out-bound trip. The round-trip took 9 hours and 10 minutes. W

Question 993623: A pilot flew a jet from A to B, a difference of 2500 km. On the return trip, the average speed was 20% faster than the out-bound trip. The round-trip took 9 hours and 10 minutes. What was the speed (in kph) from A to B?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A pilot flew a jet from A to B, a difference of 2500 km. On the return trip, the average speed was 20% faster than the out-bound trip. The round-trip took 9 hours and 10 minutes. What was the speed (in kph) from A to B?
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A to B DATA:
dist = 2500 km ; rate = 1.2x ; time = 2500/1.2x hrs
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B to A DATA:
dist = 2500 km ; rate = x km/h ; time = 2500/x hrs
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Equation:
2500/1.2x + 2500/x = 9.167 hrs
2500x + 2500*1.2x = 9.167x(1.2)x
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5500x = 11x^2
11x(x-500) = 0
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Positive solution:
x = 500
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Ans: A to B rate = 1.2*500 = 600 km/h
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cheers,
Stan H.
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