CAR speed time distance FAST r+24 t-1 90 SLOW r t 90
Let speed of slower car be S
Then speed of faster car is: S + 24
We then get:
90(S + 24) = 90S + S(S + 24) -------- Multiplying by LCD, S(S + 24)
(S - 36)(S + 60) = 0
S, or speed of slower car =mph