SOLUTION: A boardwalk is parallel to and 210 ft inland from a straight shoreline. A sandy beach lies between the boardwalk and the shoreline. A man is standing on the boardwalk, exactly 750

Question 987387: A boardwalk is parallel to and 210 ft inland from a straight shoreline. A sandy beach lies between the boardwalk and the shoreline. A man is standing on the boardwalk, exactly 750 ft across the sand from his beach umbrella, which is right at the shoreline. The man walks 4 ft/s on the boardwalk and 2 s on the sand. How far should he walk on the boardwalk before veering off onto the sand if he wishes to reach his umbrella in exactly 4 min 45 s?
Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

He walks at 4 feet per second for a distance of , then at 2 feet per second for a distance of . Time is distance divided by rate, so:

is the number of seconds required to walk the entire distance. Set this expression equal to the number of seconds in 4 minutes 45 seconds and then solve for . Then calculate for the answer to the question as posed.

John

My calculator said it, I believe it, that settles it

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Actually, it comes out to him walking 720' on the boardwalk to a point opposite from the umbrella. Takes a 90 degree left turn walks 210' ft across the sand.
:
Change 4 min 45 sec to 285 sec
time = +
time = 180 + 105
time = 285 sec which is 4 min 45 sec
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