SOLUTION: A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel

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Question 984733: A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!

GOING         r             ()          d
RETRG         v             ()          d
Total                       t


r=40,v=45,t=4
unknown variables: d




Basic uniform rates rule for travel, RT=D relating rate, time, distance. Use the idea to fill the missing time expressions.


GOING         r             d/r          d
RETRG         v             d/v          d
Total                       t



Equation from the data is .

STEPS TO SOLVE FOR d:





Substitute and evaluate.

Answer by MathTherapy(10553)   (Show Source): You can put this solution on YOUR website!

A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel
Let distance, one-way, be D
Then time taken to travel on 1st trip:
Time taken to travel on 2nd trip:
Since round-trip took 4 hours, then we can say that:

-------- Multiplying by LCD, 360
17D = 1,440
D, or distance = , or miles
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