SOLUTION: Two trains leave towns 915 mi apart at the same time and travel toward each other. One train travels 13 mi/h faster than the other. If they meet in 5 hours, what is the rate of eac
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Question 983897: Two trains leave towns 915 mi apart at the same time and travel toward each other. One train travels 13 mi/h faster than the other. If they meet in 5 hours, what is the rate of each train?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two trains leave towns 915 mi apart at the same time and travel toward each other. One train travels 13 mi/h faster than the other. If they meet in 5 hours, what is the rate of each train?
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Slower train DATA:
time = 5 hrs ; rate = x mph ; distance = t*r = 5x miles
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Faster train DATA:
time = 5 hrs ; rate = x+13 mph ; distance = t*r = 5x + 65 miles
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Equation:
dist + dist = 915
5x + 5x+65 = 915
10x = 850
x = 85 mph (rate of the slower train)
x+13 = 98 mph (rate of the faster train)
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Cheers,
Stan H.
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