SOLUTION: A person covers a certain distance on car. Had he moved 30 km/hr faster, he would have taken 2.5 hrs less. If he has moved 10 km h slower, he would have taken 2.5hrs more. What is

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Question 983571: A person covers a certain distance on car. Had he moved 30 km/hr faster, he would have taken 2.5 hrs less. If he has moved 10 km h slower, he would have taken 2.5hrs more. What is his original speed.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39799)   (Show Source): You can put this solution on YOUR website!
                speed        time       distance    EQUATIONS
NORMAL           r            t          d          rt=d
FASTER          r+30         t-2.5       d          (r+30)(t-2.5)=d
SLOWER          r-10         t+2.5       d          (r-10)(t+2.5)=d


Additional equation might help:          (r+30)(t-2.5)=(r-10)(t+2.5)


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FAST equation



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SLOW equation


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The additional equation in the table is not necessary.

The equations as found can be simplified for convenience if multiply each by 2.
Those as a system of equations:

and then further


Elimination Method is perfectly convenient for the system.




Answer by MathTherapy(10810)   (Show Source): You can put this solution on YOUR website!

A person covers a certain distance on car. Had he moved 30 km/hr faster, he would have taken 2.5 hrs less. If he has moved 10 km h slower, he would have taken 2.5hrs more. What is his original speed.
Original speed:  km/h 

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