SOLUTION: After Hurricane Katrina, a rescue vehicle leaves a station at noon and heads for New Orleans. An hour later a second vehicle traveling 10 mph faster leaves the same station. By 4:0

Question 976562: After Hurricane Katrina, a rescue vehicle leaves a station at noon and heads for New Orleans. An hour later a second vehicle traveling 10 mph faster leaves the same station. By 4:00 p.m., the first vehicle reaches its destination, and the second is still 10 mi away. How fast is each vehicle?
Answer
Found 2 solutions by lwsshak3, josgarithmetic:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
After Hurricane Katrina, a rescue vehicle leaves a station at noon and heads for New Orleans. An hour later a second vehicle traveling 10 mph faster leaves the same station. By 4:00 p.m., the first vehicle reaches its destination, and the second is still 10 mi away. How fast is each vehicle?
***
let x=speed of 1st vehicle
x+10=speed of 2nd vehicle
distance=speed*travel time
..
4x=3(x+10)+10
4x=3x+30+10
x=40
x+10=50
speed of 1st vehicle=40 mph
speed of 2nd vehicle=50 mph
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
r, rate of either but only one of the vehicles;
d, the distance each vehicle travels to the rescue site;
t, ... time...

__________________speed___________time__________distance
vehicleOne_______(_r_)_____________4_____________d
vehicleTwo_______(r+10)____________4_____________d-10

Reading and carefully thinking on the desciption a few times is necessary to decide how to fill the data table cells. Observe that no variable for time were used.

You want to formulate equations and solve for the unknown variable r; and you can also solve for d if you want.

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