SOLUTION: Paul travels from a to b at an average speed of 90 km/h
He travels for "T" hours
Mary travels the same journey at an average speed of 70 km/h
She travels for 1 hour longer tha
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Question 972299: Paul travels from a to b at an average speed of 90 km/h
He travels for "T" hours
Mary travels the same journey at an average speed of 70 km/h
She travels for 1 hour longer than Paul.
what is the value of T?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Paul travels from a to b at an average speed of 90 km/h
He travels for "T" hours
Mary travels the same journey at an average speed of 70 km/h
She travels for 1 hour longer than Paul.
what is the value of T?
:
T = Paul's travel time
then
(t+1) = Mary's travel time (traveled 1 hr longer)
Write a distance equation: dist = speed * time
Paul's dist = Mary's dist
90t = 70(t+1)
90t = 70t + 70
90t - 70t = 70
20t = 70
t = 70/20
t = 3.5 hrs
:
:
Confirm this by finding the distance each traveled, should be the same
90*3.5 = 315 mi
70*4.5 = 315 mi
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