SOLUTION: Pam and Kate are walking the same path. When Pam starts walking Kate is 60 feet ahead of her. If Pam constant rate of walking is 25 feet per 7 seconds and Kate walks as 1/2 as fast

Question 969510: Pam and Kate are walking the same path. When Pam starts walking Kate is 60 feet ahead of her. If Pam constant rate of walking is 25 feet per 7 seconds and Kate walks as 1/2 as fast as Pam walks. How many seconds would it take for Pam to catch up to Kate?
Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
33.6 seconds ANSWER
Distance must be the same. Let x=seconds.
Kate is 60 feet + (12.5 ft/7 seconds) * x
Pam is walking at 25 ft/7 seconds *x
They will walk for the same time, so x is a reasonable variable. Their distance must equal.
60 + (12.5 x/7)= 25 x/7
Clear fractions by multiplying everything by 7.
420+12.5 x= 25 x
subtract 12.5 x from each side
420=12.5 x
x=33.6 seconds
Check 25 feet in 7 seconds is 3.571 ft/sec. For Kate, it is half that or 1.79 ft/sec.
In 33.6 seconds, Kate walks 59.99 or 60 feet. She has gone 120 feet, because she had a 60 foot head start.
In 33.6 seconds, Pam walks 119.88 feet. With rounding, this is 120 feet.
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
_____________________rate___________time___________distance
Pam______________________________t_______________d+60
Kate___________________________t_________________d

If the table of data makes sense (or when it makes sense), then you know what to do.
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