SOLUTION: when fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz travels to work if the train travels an average of 15

Question 96658: when fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz travels to work if the train travels an average of 15 mph faster than his driving.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
D=RT
SEEING AS THE DISTANCES ARE EQUAL THEN
R(40/60)=(R+15)(30/60)
40R/60=(30R+450)/60 HERE WE CAN ELIMINATE THE DENOMINATORS THUS WE HAVE LEFT:
40R-30R=450
10R=450
R=450/10
R=45 MPH FOR THE DRIVE WHILE THE TRAIN'S RATE IS:
45+15=60 MPH FOR THE TRAIN.
PROOF
45(40/60)=60(30/60)
45*40=60*30
1800=1800

RELATED QUESTIONS
when fritz drives to work his trip takes 48 minutes, but when he takes the train it takes (answered by stanbon)

When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes (answered by Paul)

When Fritz drives to work his trip takes 40 minutes, but when he takes the train it takes (answered by stanbon)

When Fritz drives to work his trip takes 48 minutes, but when he takes the train it takes (answered by lwsshak3)

When Fritz drives to work his trip takes 36 minutes, but when he takes the train... (answered by josgarithmetic,jorel555)

When Fritz drives to work his trip takes 36 minutes, but when he takes the train... (answered by josgarithmetic)

When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes (answered by ankor@dixie-net.com)

When Fritz drives to work his trip takes 36 minutes but when he takes the train it takes... (answered by lwsshak3)

When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes (answered by ankor@dixie-net.com)