SOLUTION: Greg drove at a constant speed in a rainstorm for 294 miles. He took a break, and the rain stopped. He then drove 156 miles at a speed that was 3 mph faster than his pervious speed

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Question 965068: Greg drove at a constant speed in a rainstorm for 294 miles. He took a break, and the rain stopped. He then drove 156 miles at a speed that was 3 mph faster than his pervious speed. If he drove for 9 hours, find the cars speed for each part of the trip.
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = time in hours for 1st trip
= time in hours for 2nd trip
---------------------

Multiply both sides by




-------------------------
Use quadratic formula:




First find
Find
Then find
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Greg drove at a constant speed in a rainstorm for 294 miles. He took a break, and the rain stopped. He then drove 156 miles at a speed that was 3 mph faster than his pervious speed. If he drove for 9 hours, find the cars speed for each part of the trip.
Let speed during 1st leg of trip, be S

Then speed during 2nd leg = S + 3

Time taken to complete 1st leg: 

Time taken to complete 2nd leg: 

We then get: 

294(S + 3) + 156S = 9(S)(S + 3) ------- Multiplying by LCD, S(S + 3)













(S - 49)(S + 2) = 0  

S, or speed on 1st leg =  mph            OR           S = - 2 (ignore)

Speed on 2nd leg: 49 + 3, or  mph 

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