SOLUTION: Two men start together a walk a certain distance at 3.75 km and 3km/hr respectively. The former arrives 30 minutes before the distance to be walked is?

Question 962668: Two men start together a walk a certain distance at 3.75 km and 3km/hr respectively. The former arrives 30 minutes before the distance to be walked is?
Found 2 solutions by Alan3354, addingup:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Two men start together a walk a certain distance at 3.75 km and 3km/hr respectively. The former arrives 30 minutes before the distance to be walked is?
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Makes no sense.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Distance = rate*time and we know the rate but not the time (how long they walked). So let's find out.
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One walked at a rate of 3.75/hr and the other at a rate of 3/hr. Next it says that it took the second walker 30 minutes more. But wait, 3.75 and 3 are per HOUR and we cannot mix hours and minutes, we have to convert. 30 minutes is 1/2 hour, in decimals 30 minutes is .5 of an hour. Now we have apples with apples.
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3.75t = 3(t+.5)Note that we equalized both sides by adding 1/2 hour
3.75t = 3t+1.5 subtract 3t from both sides:
.75t= 1.5 Divide both sides by .75
t= 2 This is how long Mr. 3.75 walked.
3.75*2= 7.5 is how many km they walked
Proof:
7.5/3.75= 2 hours
7.5/3 = 2.5 hours, it took Mr. 3km .5 hours (30 minutes) longer to complete the 7.5km

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