SOLUTION: Sally had a doctor's appt. at 10am and decided she would take the bus. It took her 10 min. to get to her appt. riding the bus. She decided that she would jog hom (by the same rou

Question 95954: Sally had a doctor's appt. at 10am and decided she would take the bus. It took her 10 min. to get to her appt. riding the bus. She decided that she would jog hom (by the same route) after the appt. Jogging home took her 48 min. The bus traveled 25 min. mph faster going to the appt. than Sally did jogging home. Find the speed of the bus and Sally's jogging speed.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Sally had a doctor's appt. at 10am and decided she would take the bus. It took her 10 min. to get to her appt. riding the bus. She decided that she would jog hom (by the same route) after the appt. Jogging home took her 48 min. The bus traveled 25 min. mph faster going to the appt. than Sally did jogging home. Find the speed of the bus and Sally's jogging speed.
:
Change 10 min to hrs: 10/60 = 1/6 hr
Change 48 min to hrs: 48/60 = 4/5 hr
:
Let x = S's jogging speed
Then
(x+25) = Bus speed
:
We know jogging dist and bus distance are the same. Write and equation from this fact:
Dist = time * speed
Bus dist = jog dist
(x+25) = x
:
=
:
Cross multiply:
6(4x) = 5(x+25)
24x = 5x + 125
25x - 5x = 125
19x = 125
x = 125/19
x = 6.579 mph is her jogging speed
then
6.579 + 25 = 31.579 mph is the bus speed
:
:
Check solution by finding if, indeed, the distances are equal:
Using decimals 1/6 = .167 and 4/5 = .8
.167 * 31.579 = 5.27 mi
.8 * 6.579 = 5.26 mi, close enough
:
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