SOLUTION: On a flight from Chicago to Los Angeles, there was a tailwind (with wind). On the return flight that same day, the airplane was flying into a headwind (against the wind). Suppose

Question 957321: On a flight from Chicago to Los Angeles, there was a tailwind (with wind). On the return flight that same day, the airplane was flying into a headwind (against the wind). Suppose an airplane has an average speed of 450 mph in still air and the wind was a constant speed for both flights, what was the speed of the wind if Chicago and Los Angeles are 2015 miles apart and the flights took a combined time of 9 hours.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
W=wind speed
Multiply by (450mph-W)(450mph+W)

Add 9W^2-1813500mi^2hr^2 to each side.
Divide each side by 9.
Find square root of each side.
ANSWER: The wind speed was 31.62 miles per hour.
CHECK:

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