SOLUTION: An aeroplane flies from A to B at a speed of 750km/h. On the returnn trip there was a strong tail wind and airplane flew at 900km/h. The return trip took 20min less than original.

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Question 954012: An aeroplane flies from A to B at a speed of 750km/h. On the returnn trip there was a strong tail wind and airplane flew at 900km/h. The return trip took 20min less than original. How many hours did the return trip take?
Found 3 solutions by josgarithmetic, hemu_da, MathTherapy:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!
R=900
r=750
t, unknown time length going A to B.
k=1/3 hour, how much time less on returning, B to A
Question asks for t-1/3;
Understand that 20 minutes is of an hour.


_________________speed__________time________distance
GOTO_____________r_______________t__________d
BACK_____________R_____________t-k________d

Basic uniform rates of travel fact, RT=D

EQUATIONS:








What is really wanted, if keeping in symbols first, is



Substitute the values to finish.
Answer by hemu_da(13)   (Show Source): You can put this solution on YOUR website!
Suppose t is the normal time to travel from A to B.
And normal speed is 750 km/hr.
Speed on return trip is 900 km/hr.
.
.
Time taken is 20 min less than the original ( which is t here).
.
.
I.e. hr
.
.
In both the trip distance is same that is...
.
.

.
.
5t = 6t - 2
t = 2 hr.
.
.
Returning trip take 20 min less than the original, hence time is--
.
.
2 hr - 20 min = 1 hr 40 min.
.....
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

An aeroplane flies from A to B at a speed of 750km/h. On the returnn trip there was a strong tail wind and airplane flew at 900km/h. The return trip took 20min less than original. How many hours did the return trip take?
Let time taken on return trip (B to A), be T

Then time taken on outbound trip (A to B) = , or 

We then get: 

750T + 250 = 900T

750T – 900T = - 250 

- 150T = - 250

T, or time taken on return trip = , or  hours 

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