SOLUTION: two trains are 412 miles apart, and their speeds differ by 19mph. Find the speed of each train if they are traveling toward eachother and will meet in 4 hours?

Question 952996: two trains are 412 miles apart, and their speeds differ by 19mph. Find the speed of each train if they are traveling toward eachother and will meet in 4 hours?
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
The total distance is 412 and they're traveling toward each other. Therefore A + B = 412 (the distance from train A to train B).
Train A = Train B + (19*4) [19 mph more times 4 hours]
A = B + 76
We know from the first part that A + B = 412
Let's substitute the known value of A from the second equation into the first.
(B+76) + B = 412
2B + 76 = 412
2B = 336
B = 168
If B is 168, then A is 412-168 = 244
That's for 4 hours.
168/4 = 42mph for Train B
244/4 = 61mph for Train A
61mph is indeed 19mph more than 42mph.
Success!
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